How many and gates are required for a 3 to 8 decoder?

How many and gates are required for a 3 to 8 decoder?

From the above Boolean expressions, the implementation of 3 to 8 decoder circuit can be done with the help of three NOT gates & 8-three input AND gates. In the above circuit, the three inputs can be decoded into 8 outputs, where every output represents one of the midterms of the three input variables.

What is the maximum number of outputs of a 3-to-8 line decoder that can be active at once?

A 3-to-8 line decoder activates one of eight output bits for each input value from 0 to 7 — the range of integer values that can be expressed in three bits. Similarly, a 4-to-16 line decoder activates one of 16 outputs for each 4-bit input in the integer range [0,15].

What is E in decoder?

In a 3 to 8 line decoder, there is a total of eight outputs, i.e., Y0, Y1, Y2, Y3, Y4, Y5, Y6, and Y7 and three outputs, i.e., A0, A1, and A2. This circuit has an enable input ‘E’. Just like 2 to 4 line decoder, when enable ‘E’ is set to 1, one of these four outputs will be 1.

How is a decoder used in a Verilog circuit?

Decoders are combinational circuits used for breaking down any combination of inputs to a set of output bits that are all set to ‘0’ apart from one output bit. Therefore when one input changes, two output bits will change.

What are the input and output bits of Verilog?

The number of input bits are 3 and number of output bits are 8. //declare the Verilog module – The inputs and output port names. //what are the input ports and their sizes. //what are the output ports and their sizes.

What kind of decoder is N to 2n?

A n to 2n decoder is a combinatorial logic device which has n input lines and 2n output lines. For each possible combination of n input binary lines, one and only one output signal will be logic 1. Thus, the decoder is a min-term generator in which each output corresponds to one min-term.