What is the formula for the sum of cubes of first n numbers?

What is the formula for the sum of cubes of first n numbers?

The formula to find the sum of cubes of n natural numbers is S = [n2 (n + 1)2]/4, where n is the count of natural numbers that we take.

How do you find the sum of the first n even numbers?

Sum of first n even numbers = n * (n + 1).

What are the cubes of even numbers?

(i) Cubes of an even number are 216, 8000, 4096. (ii) Cubes of an odd number are 729, 3375, 125, 343, 9261.

What is the formula of sum of cubes?

The sum of cubes formula is one of the important algebraic identity. It is represented by a3 + b3 and is read as a cube plus b cube. The sum of cubes (a3 + b3) formula is expressed as a3 + b3 = (a + b) (a2 – ab + b2).

What is the sum of n even numbers?

The formula is: Sum of Even Numbers Formula = n(n+1) where n is the number of terms in the series.

What is sum of n even numbers?

What is the formula for even numbers?

FAQs on Sum of Even Numbers The formula to find the sum of even numbers is n(n+1), where n is the natural number.

Which of the following are cubes of even number 64?

64 and 27 is correct Sis or Bro.

Which of the following are cubes of even number 9261?

Therefore, 9261 is the cube of 21.

How do you find the sum and difference of cubes?

For the difference of cubes, the “minus” sign goes in the linear factor, a – b; for the sum of cubes, the “minus” sign goes in the quadratic factor, a2 – ab + b2.

What is the sum of the first n numbers?

The formula of the sum of first n natural numbers is S=n(n+1)2 . If the sum of first n natural number is 325 then find n.

What is the sum of cubes of even numbers?

Sum of cubes of even and odd natural numbers. We know that sum of cubes of first n natural numbers is = (n(n+1)/2) 2. Sum of cube of first n even natural numbers. 2 3 + 4 3 + 6 3 + ……… + (2n) 3. Even Sum = 2 3 + 4 3 + 6 3 + …. + (2n) 3 if we multiply by 2 3 then = 2 3 x (1 3 + 2 3 + 3 2 + …. + (n) 3) = 2 3 + 4 3 + 6 3 + ………

How to calculate the sum of first n even numbers?

Efficient Approach: By applying the formula given below. Sum of first n even numbers = n * (n + 1). Sum of first n terms of an A.P. (Arithmetic Progression) = (n/2) * [2*a + (n-1)*d] ….. (i) where, a is the first term of the series and d is the difference between the adjacent terms of the series.

What is the sum of cubes of odd natural numbers?

Sum of cubes of even and odd natural numbers. We know that sum of cubes of first n natural numbers is = (n(n+1)/2) 2. Sum of cube of first n even natural numbers. 2 3 + 4 3 + 6 3 + ……… + (2n) 3. Even Sum = 2 3 + 4 3 + 6 3 + ….