How do you calculate the density of NaOH?
Just calculate the following: d {g/L}=(c {mol/L} * v {L}) * mw {g/mol} / v {L}; here, (c * v) * mw gives the mass of your NaOH solution (providing that v is given in liters), and further dividing it to v gives the density. So just multiply the concentration with molecular weight, that gives the density in g/L.
What is the molarity m of a N 40% NaOH solution MW 40.00 g mol )?
The molarity of $40\% $ NaOH solution is $12M$.
What is the density of a 12% NaOH solution?
1.131 g/mL
A solution containing 12.0% sodium hydroxide by mass has a density of 1.131 g/mL.
How do you calculate NaOH?
Step 1: Calculate the amount of sodium hydroxide in moles
- Amount of solute in mol = concentration in mol/dm 3 × volume in dm 3
- Amount of sodium hydroxide = 0.100 × 0.0250.
- = 0.00250 mol.
- The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H 2O(l)
- So the mole ratio NaOH:HCl is 1:1.
What is the density of NaOH?
2.13 g/cm³
Sodium hydroxide/Density
What is the density of sodium hydroxide in g mL?
1.515g/mL
Specifications
| Concentration | 50% in H2O |
|---|---|
| Linear Formula | NaOH |
| Density | 1.515g/mL at 25°C |
| UN Number | UN1824 |
| Formula Weight | 40g/mol |
What is the density of 50% NaOH?
What is the molarity m of a N 50% NaOH solution MW 40.00 g mol )?
40 g of NaOH is equal to 1 mole. 1 g of NaOH will be equal to 1 40 moles. Therefore, we can say that 1 liter of sodium hydroxide solution contains 18.9375 moles or in other words molarity of 50% (w/w) Sodium Hydroxide is equal to 18.9375 M.
What is the density of 25% NaOH?
What is concentration of NaOH?
Sodium hydroxide (NaOH, caustic soda, lye) is a strong alkali (base). It is used as flakes, granules or as an aqueous solution, mostly at concentrations of 48 % to 50 %.