## Is sin x uniformly continuous?

So g(x) = sin x is Lipschitz on R, and hence uniformly continuous. To show that x sin x is not uniformly continuous, we use the third criterion for nonuniform continuity. So x sin x is not uniformly continuous. #8) Let ϵ > 0.

### Why is Sinx X not continuous?

It is undefined till you define it since the expression sin(x)/x is indeterminate at x=0. However it has a limit of 1 as x approaches zero. If you define a function to take the value 1 when x=0 and the value sin(x)/x for x≠0 then that function is continuous at zero.

**Why is sin x 2 not uniformly continuous?**

The oscillations in sin(x2) get faster and faster, on arbitrarily small intervals the function changes its value from 0 to 1.

**Is sin x always continuous?**

The function sin(x) is continuous everywhere. The function cos(x) is continuous everywhere.

## How is sin x continuous?

be any real number. That is when approached from the left hand side and the right hand side we get the same value which means the function is continuous. Therefore, the function sine is continuous for every real number.

### Is sinx continuous for all real numbers?

**Is sin x 3 uniformly continuous?**

f(x)=sinx3 for x∈R is not uniformly continuous. In this case its derivative f′(x)=3x2sinx3 which is unbounded.

**Is X COS X uniformly continuous?**

Here, limx↦0cosxx does’t exist, we cannot continuously extend f on [0,1]. So f is not uniformly continuous on (0,1).

## Why is sin x continuous everywhere?

f is continuous if you can graph it without lifting your pencil from the paper. with p(x),q(x) polynomials, are continuous wherever defined (so f is continuous wherever q(x) = 0). sin x = sin c, so sin x is continuous for all x. Similarly for cos x.

### Is x 2 uniformly continuous on R?

The function f (x) = x2 is not uniformly continuous on R. δ =2+1/n2 δ > ε.